An Apodization Function
  | 
(1) | 
 
having Instrument Function
The peak (in units of 
) is 2.  The extrema are given by letting 
 and solving
  | 
(3) | 
 
  | 
(4) | 
 
  | 
(5) | 
 
Solving this numerically gives 
, 
, 
, ...for the first few solutions. The
second of these is the peak Positive sidelobe, and the third is the peak Negative sidelobe.  As a fraction of the peak, 
they are 0.128375 and 
.  The Full Width at Half Maximum is found by setting 
 
  | 
(6) | 
 
and solving for 
, yielding
  | 
(7) | 
 
Therefore, with 
,
  | 
(8) | 
 
See also Apodization Function
 
© 1996-9 Eric W. Weisstein 
1999-05-26